Q. Q. Q.
f(x) = x² - 6x + 9
f[tex]\sf^{-1}[/tex](x) = ...
____
persamaan kuadrat bkn si? v:![]()
f(x) = x² - 6x + 9
f[tex]\sf^{-1}[/tex](x) = ...
____
persamaan kuadrat bkn si? v:
Penjelasan dengan langkah-langkah:
f(x) = x² – 6x + 9
f(x) = (x – 3)²
x – 3 = √y
x = 3 ± √y
f-¹(x) = 3 ± √x
f(x) = ax² + bx + c
maka, f-¹(x) = -b ± √b² - 4a(c - x) /2a
..
f(x) = x² - 6x + 9
- a = 1
- b = -6
- c = 9
f-¹(x) = 6 ± √(-6)² - 4(1)(9 - x) /2(1)
f-¹(x) = 6 ± √36 - 4(9 - x)/2
f-¹(x) = 6 ± 2√36 - 36 + x /2
f-¹(x) = 6 ± 2√0 + x /2
f-¹(x) = 6 ± 2√x /2
f-¹(x) = 3 ± √x
[answer.2.content]
